Pair of Linear Equations: Substitution and Elimination Methods
Worked example: substitution
Solve x+y=14 and x−y=4 by substitution.
Solution: From the second equation, x=y+4. Substituting into the first:
(y+4)+y=14⇒2y=10⇒y=5So x=5+4=9. Checking: 9+5=14 and 9−5=4, both correct.
Worked example: substitution revealing infinitely many solutions
Solve 3x−y=3 and 9x−3y=9 by substitution.
Solution: From the first, y=3x−3. Substituting into the second:
9x−3(3x−3)=9⇒9x−9x+9=9⇒9=9Every variable canceled out, leaving a statement that's always true. That's the signal that the second equation is just 3× the first, the same line twice, with infinitely many solutions rather than one.
Worked example: elimination
Solve x+y=5 and 2x−3y=4 by elimination.
Solution: Multiply the first equation by 2 so the x terms match:
2x+2y=10Subtracting 2x−3y=4 from this eliminates x:
(2x+2y)−(2x−3y)=10−4⇒5y=6⇒y=56Substituting back: x+56=5⇒x=519.
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Cross-multiplication packages the same elimination idea into one formula, and works even on equations that don't look linear at first, once you substitute for the messy part.