Eigenvalues and Eigenvectors

The defining equation

For a square matrix AA, an eigenvector is a nonzero vector vv that AA only stretches or shrinks along its own line: multiplying by AA is the same as multiplying by a number λ\lambda, the eigenvalue:

Av=λv⟺(A−λI)v=0Av = \lambda v \quad\Longleftrightarrow\quad (A-\lambda I)v = 0

Since v≠0v \ne 0, this has a solution only when A−λIA-\lambda I is singular, which gives the characteristic equation:

det⁡(A−λI)=0\det(A - \lambda I) = 0

Worked example

Find the eigenvalues and eigenvectors of A=[2112]A = \begin{bmatrix} 2 & 1 \\ 1 & 2 \end{bmatrix}.

det⁡[2−λ112−λ]=(2−λ)2−1=0  ⇒  λ=1 or λ=3\det\begin{bmatrix} 2-\lambda & 1 \\ 1 & 2-\lambda \end{bmatrix} = (2-\lambda)^2 - 1 = 0 \;\Rightarrow\; \lambda = 1 \text{ or } \lambda = 3

For λ=1\lambda=1: (A−I)v=0(A-I)v=0 gives v1+v2=0v_1+v_2=0, so v=[1−1]v = \begin{bmatrix}1\\-1\end{bmatrix}. For λ=3\lambda=3: (A−3I)v=0(A-3I)v=0 gives v1=v2v_1=v_2, so v=[11]v = \begin{bmatrix}1\\1\end{bmatrix}.

Check by substitution: A[1−1]=[1−1]A\begin{bmatrix}1\\-1\end{bmatrix} = \begin{bmatrix}1\\-1\end{bmatrix} and A[11]=[33]A\begin{bmatrix}1\\1\end{bmatrix} = \begin{bmatrix}3\\3\end{bmatrix}. Check by trace and determinant: 1+3=4=2+21+3 = 4 = 2+2 and 1×3=3=4−11\times3 = 3 = 4-1.

Worked example: a non-symmetric matrix

Find the eigenvalues and eigenvectors of B=[4123]B = \begin{bmatrix} 4 & 1 \\ 2 & 3 \end{bmatrix}.

det⁡(B−λI)=(4−λ)(3−λ)−2=λ2−7λ+10=(λ−2)(λ−5)\det(B-\lambda I) = (4-\lambda)(3-\lambda) - 2 = \lambda^2 - 7\lambda + 10 = (\lambda-2)(\lambda-5)

For λ=5\lambda=5: −v1+v2=0-v_1+v_2=0, so v=[11]v = \begin{bmatrix}1\\1\end{bmatrix}. For λ=2\lambda=2: 2v1+v2=02v_1+v_2=0, so v=[1−2]v = \begin{bmatrix}1\\-2\end{bmatrix}. Checks: 2+5=7=trace(B)2+5 = 7 = \text{trace}(B) and 2×5=10=det⁡B2\times5 = 10 = \det B.

Shortcuts worth knowing

If A has eigenvalue λ (with the same eigenvector)
MatrixEigenvalueFor B above (λ = 2, 5)
A2A^2λ2\lambda^24, 25
A−1A^{-1} (if AA is invertible)1/λ1/\lambda1/2, 1/5
A+kIA + kIλ+k\lambda + kwith k=3k = 3: 5, 8
kAkAkλk\lambdawith k=2k = 2: 4, 10

For a triangular (or diagonal) matrix the eigenvalues are the diagonal entries: [25−103400−1]\begin{bmatrix} 2 & 5 & -1 \\ 0 & 3 & 4 \\ 0 & 0 & -1 \end{bmatrix} has eigenvalues 2, 3 and −1. A real symmetric matrix always has real eigenvalues.

Common mistakes

  • Writing det⁡(A)−λ=0\det(A) - \lambda = 0. Subtract λ\lambda from every diagonal entry first, then take the determinant.
  • Accepting v=0v = 0 as an eigenvector. Eigenvectors are nonzero by definition; any nonzero multiple of a valid one also works.
  • Skipping the checks. The sum of eigenvalues must equal the trace and their product the determinant. If either fails, the characteristic equation has a slip.
  • Assuming eigenvalues of A+BA+B are sums of eigenvalues. That holds for A+kIA+kI, not for two general matrices.

Where this comes up in exams

Eigenvalues and eigenvectors are listed under Linear Algebra in the GATE 2027 syllabi for CS, EC, EE, IN and ME (the EC syllabus writes 'eigen values and eigen vectors').

Checked against GATE 2027 CS syllabus, GATE 2027 EC syllabus, GATE 2027 EE syllabus, GATE 2027 IN syllabus and GATE 2027 ME syllabus. Syllabi can change from year to year, so confirm with the latest official notification for your exam.

Continue learning

The same partial derivatives that build a Jacobian matrix are covered separately, and a matrix's trace and determinant connect to its other properties.

From past GATE papers